annotate FChTransformUtils.cpp @ 10:af59167b3d35 perf

size_t -> int throughout: permits better optimisation for tight for-loops, making the whole thing about 10% faster
author Chris Cannam
date Tue, 02 Oct 2018 13:21:15 +0100
parents 7ec763dc767c
children 44b86c346a5a
rev   line source
Chris@0 1 /*
Chris@0 2 copyright (C) 2012 I. Irigaray, M. Rocamora
Chris@0 3
Chris@0 4 This program is free software: you can redistribute it and/or modify
Chris@0 5 it under the terms of the GNU General Public License as published by
Chris@0 6 the Free Software Foundation, either version 3 of the License, or
Chris@0 7 (at your option) any later version.
Chris@0 8
Chris@0 9 This program is distributed in the hope that it will be useful,
Chris@0 10 but WITHOUT ANY WARRANTY; without even the implied warranty of
Chris@0 11 MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
Chris@0 12 GNU General Public License for more details.
Chris@0 13
Chris@0 14 You should have received a copy of the GNU General Public License
Chris@0 15 along with this program. If not, see <http://www.gnu.org/licenses/>.
Chris@8 16 */
Chris@0 17
Chris@0 18
Chris@0 19 #include "FChTransformUtils.h"
Chris@0 20 #include <math.h>
Chris@0 21
Chris@10 22 void cumtrapz(const double *x, const double *y, int N, double *accum)
Chris@0 23 /*Trapezoidal Integrator: 1/2(b-a)(F(a)+F(b))*/
Chris@0 24 {
Chris@8 25 accum[0]=0.0;
Chris@10 26 for (int i = 1; i < N; i++) {
Chris@8 27 accum[i]=accum[i-1]+0.5*(x[i]-x[i-1])*(y[i]+y[i-1]);
Chris@8 28 }
Chris@0 29 }
Chris@0 30
Chris@0 31
Chris@10 32 void interp1(const double *x1, const double *y1, int N1, const double *x2, double *y2, int N2){
Chris@0 33 /*1-D linear interpolation*/
Chris@0 34
Chris@10 35 for (int i = 0; i < N2; i++) {
Chris@8 36 /*Smaller or equal than the smallest, or larger or equal than the largest.*/
Chris@8 37 if ( x2[i] <= x1[0] ) {
Chris@8 38 y2[i] = y1[0];
Chris@8 39 } else if ( x2[i] >= x1[N1-1] ) {
Chris@8 40 y2[i] = y1[N1-1];
Chris@8 41 } else {
Chris@8 42 /*Search every value of x2 in x1*/
Chris@10 43 int j = 1;
Chris@10 44 int salir = 0;
Chris@8 45 while ((j<N1)&&(!salir)) {
Chris@8 46 if ( x2[i] <= x1[j] ) {
Chris@8 47 y2[i] = y1[j-1] + ( ( y1[j] - y1[j-1] )*(x2[i] - x1[j-1] ) )/ ( x1[j] - x1[j-1] );
Chris@8 48 salir = 1;
Chris@8 49 } // if
Chris@8 50 j++;
Chris@8 51 } // for
Chris@8 52 } // else
Chris@8 53 } // for
Chris@0 54
Chris@0 55 }
Chris@0 56
Chris@10 57 void interp1q(const double *y1, const int *x2_int, const double *x2_frac, double *y2, int N2){
Chris@0 58
Chris@10 59 for(int i=0;i<N2;i++){
Chris@8 60 y2[i] = y1[x2_int[i]]*(1.0-x2_frac[i])+y1[x2_int[i]+1]*x2_frac[i];
Chris@8 61 } // for
Chris@0 62
Chris@0 63 }
Chris@0 64
Chris@10 65 void hanning_window(double *p_window, int n, bool normalize) {
Chris@0 66
Chris@8 67 double accum=0;
Chris@10 68 for (int i = 0; i < n; i++) {
Chris@0 69 p_window[i] = 0.5*(1.0-cos(2*M_PI*(double)(i+1)/((double)n+1.0)));
Chris@0 70 accum += p_window[i];
Chris@0 71 }
Chris@8 72 if (normalize) {
Chris@10 73 for (int i = 0; i < n; i++) { //window normalization
Chris@8 74 p_window[i] = p_window[i]/accum;
Chris@0 75 }
Chris@8 76 }
Chris@0 77
Chris@0 78 }