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Current fftw source
author Chris Cannam
date Tue, 18 Oct 2016 13:40:26 +0100
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Chris@42 72 <a name="Load-balancing"></a>
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Chris@42 78 <a name="Load-balancing-1"></a>
Chris@42 79 <h4 class="subsection">6.4.2 Load balancing</h4>
Chris@42 80 <a name="index-load-balancing"></a>
Chris@42 81
Chris@42 82 <p>Ideally, when you parallelize a transform over some <em>P</em>
Chris@42 83 processes, each process should end up with work that takes equal time.
Chris@42 84 Otherwise, all of the processes end up waiting on whichever process is
Chris@42 85 slowest. This goal is known as &ldquo;load balancing.&rdquo; In this section,
Chris@42 86 we describe the circumstances under which FFTW is able to load-balance
Chris@42 87 well, and in particular how you should choose your transform size in
Chris@42 88 order to load balance.
Chris@42 89 </p>
Chris@42 90 <p>Load balancing is especially difficult when you are parallelizing over
Chris@42 91 heterogeneous machines; for example, if one of your processors is a
Chris@42 92 old 486 and another is a Pentium IV, obviously you should give the
Chris@42 93 Pentium more work to do than the 486 since the latter is much slower.
Chris@42 94 FFTW does not deal with this problem, however&mdash;it assumes that your
Chris@42 95 processes run on hardware of comparable speed, and that the goal is
Chris@42 96 therefore to divide the problem as equally as possible.
Chris@42 97 </p>
Chris@42 98 <p>For a multi-dimensional complex DFT, FFTW can divide the problem
Chris@42 99 equally among the processes if: (i) the <em>first</em> dimension
Chris@42 100 <code>n0</code> is divisible by <em>P</em>; and (ii), the <em>product</em> of
Chris@42 101 the subsequent dimensions is divisible by <em>P</em>. (For the advanced
Chris@42 102 interface, where you can specify multiple simultaneous transforms via
Chris@42 103 some &ldquo;vector&rdquo; length <code>howmany</code>, a factor of <code>howmany</code> is
Chris@42 104 included in the product of the subsequent dimensions.)
Chris@42 105 </p>
Chris@42 106 <p>For a one-dimensional complex DFT, the length <code>N</code> of the data
Chris@42 107 should be divisible by <em>P</em> <em>squared</em> to be able to divide
Chris@42 108 the problem equally among the processes.
Chris@42 109 </p>
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