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date Fri, 07 Feb 2020 11:51:13 +0000
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Chris@10 3 <title>The 1d Discrete Fourier Transform (DFT) - FFTW 3.3.3</title>
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Chris@10 49 <a name="The-1d-Discrete-Fourier-Transform-(DFT)"></a>
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Chris@10 51 <p>
Chris@10 52 Next:&nbsp;<a rel="next" accesskey="n" href="The-1d-Real_002ddata-DFT.html#The-1d-Real_002ddata-DFT">The 1d Real-data DFT</a>,
Chris@10 53 Previous:&nbsp;<a rel="previous" accesskey="p" href="What-FFTW-Really-Computes.html#What-FFTW-Really-Computes">What FFTW Really Computes</a>,
Chris@10 54 Up:&nbsp;<a rel="up" accesskey="u" href="What-FFTW-Really-Computes.html#What-FFTW-Really-Computes">What FFTW Really Computes</a>
Chris@10 55 <hr>
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Chris@10 57
Chris@10 58 <h4 class="subsection">4.8.1 The 1d Discrete Fourier Transform (DFT)</h4>
Chris@10 59
Chris@10 60 <p><a name="index-discrete-Fourier-transform-292"></a><a name="index-DFT-293"></a>The forward (<code>FFTW_FORWARD</code>) discrete Fourier transform (DFT) of a
Chris@10 61 1d complex array X of size n computes an array Y,
Chris@10 62 where:
Chris@10 63 <center><img src="equation-dft.png" align="top">.</center>The backward (<code>FFTW_BACKWARD</code>) DFT computes:
Chris@10 64 <center><img src="equation-idft.png" align="top">.</center>
Chris@10 65
Chris@10 66 <p><a name="index-normalization-294"></a>FFTW computes an unnormalized transform, in that there is no coefficient
Chris@10 67 in front of the summation in the DFT. In other words, applying the
Chris@10 68 forward and then the backward transform will multiply the input by
Chris@10 69 n.
Chris@10 70
Chris@10 71 <p><a name="index-frequency-295"></a>From above, an <code>FFTW_FORWARD</code> transform corresponds to a sign of
Chris@10 72 -1 in the exponent of the DFT. Note also that we use the
Chris@10 73 standard &ldquo;in-order&rdquo; output ordering&mdash;the k-th output
Chris@10 74 corresponds to the frequency k/n (or k/T, where T
Chris@10 75 is your total sampling period). For those who like to think in terms of
Chris@10 76 positive and negative frequencies, this means that the positive
Chris@10 77 frequencies are stored in the first half of the output and the negative
Chris@10 78 frequencies are stored in backwards order in the second half of the
Chris@10 79 output. (The frequency -k/n is the same as the frequency
Chris@10 80 (n-k)/n.)
Chris@10 81
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