Mercurial > hg > smallbox
comparison Problems/ImgDenoise_reconstruct.m @ 128:8e660fd14774 ivand_dev
Feature 186
author | Ivan Damnjanovic lnx <ivan.damnjanovic@eecs.qmul.ac.uk> |
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date | Mon, 13 Jun 2011 14:55:45 +0100 |
parents | 5a20f4936159 |
children |
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126:db5a7fe1a404 | 128:8e660fd14774 |
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1 function reconstructed=ImgDenoise_reconstruct(y, Problem, SparseDict) | 1 function reconstructed=ImgDenoise_reconstruct(y, Problem, SparseDict) |
2 %%% Pierre Villars Example - reconstruction function | 2 %% Image Denoising Problem reconstruction function |
3 % | |
4 % This reconstruction function is using sparse representation y | |
5 % in dictionary Problem.A to reconstruct the patches of the denoised | |
6 % image. | |
7 | |
3 % | 8 % |
4 % Centre for Digital Music, Queen Mary, University of London. | 9 % Centre for Digital Music, Queen Mary, University of London. |
5 % This file copyright 2009 Ivan Damnjanovic. | 10 % This file copyright 2009 Ivan Damnjanovic. |
6 % | 11 % |
7 % This program is free software; you can redistribute it and/or | 12 % This program is free software; you can redistribute it and/or |
8 % modify it under the terms of the GNU General Public License as | 13 % modify it under the terms of the GNU General Public License as |
9 % published by the Free Software Foundation; either version 2 of the | 14 % published by the Free Software Foundation; either version 2 of the |
10 % License, or (at your option) any later version. See the file | 15 % License, or (at your option) any later version. See the file |
11 % COPYING included with this distribution for more information. | 16 % COPYING included with this distribution for more information. |
12 % | 17 %% |
13 % This example is based on the experiment suggested by Professor Pierre | |
14 % Vandergheynst on the SMALL meeting in Villars. | |
15 | 18 |
16 % using sparse representation y in dictionary Problem.A reconstruct the | |
17 % patches from the target image | |
18 | 19 |
19 % stepsize % | 20 % stepsize % |
20 if (isfield(Problem,'stepsize')) | 21 if (isfield(Problem,'stepsize')) |
21 stepsize = Problem.stepsize; | 22 stepsize = Problem.stepsize; |
22 if (numel(stepsize)==1) | 23 if (numel(stepsize)==1) |