idamnjanovic@3
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1 function [A, resF]=SMALL_cgp(Dict,X, m, maxNumCoef, errorGoal, varargin)
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2 %=============================================
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3 % Sparse coding of a group of signals based on a given
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4 % dictionary and specified number of atoms to use.
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5 % input arguments: Dict - the dictionary
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6 % X - the signals to represent
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7 % m - number of atoms in Dictionary
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8 % errorGoal - the maximal allowed representation error for
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9 % each signal.
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10 %
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11 % optional: if Dict is function handle then Transpose Dictionary
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12 % handle needs to be specified.
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13 %
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14 % output arguments: A - sparse coefficient matrix.
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15 %
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16 % based on KSVD toolbox solver found on Miki Elad webpage (finding inverse
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17 % with pinv() is changed with conjugate gradient method)
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18 % Ivan Damnjanovic 2009
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19 %=============================================
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20 %%
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21 %%
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22
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23 % This Dictionary check is based on Thomas Blumensath work in sparsify 0_4 greedy solvers
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24 if isa(Dict,'float')
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25 D =@(z) Dict*z;
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26 Dt =@(z) Dict'*z;
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27 elseif isobject(Dict)
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28 D =@(z) Dict*z;
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29 Dt =@(z) Dict'*z;
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30 elseif isa(Dict,'function_handle')
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31 try
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32 DictT=varargin{1};
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33 if isa(DictT,'function_handle');
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34 D=Dict;
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35 Dt=DictT;
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36 else
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37 error('If Dictionary is a function handle,Transpose Dictionary also needs to be a function handle. ');
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38 end
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39 catch
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40 error('If Dictionary is a function handle, Transpose Dictionary needs to be specified. Exiting.');
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41 end
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42 else
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43 error('Dictionary is of unsupported type. Use explicit matrix, function_handle or object. Exiting.');
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44 end
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45 %%
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46
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47 [n,P]=size(X);
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48
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49
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50
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51 A = sparse(m,size(X,2));
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52
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53 for k=1:1:P,
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54
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55 x = X(:,k);
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56 residual = x;
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57 indx =[];
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58 j=0;
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59
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60
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61 currResNorm = residual'*residual/n;
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62 errGoal=errorGoal*currResNorm;
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63 a = zeros(m,1);
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64 p = zeros(m,1);
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65
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66 while j < maxNumCoef,
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67
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68 j = j+1;
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69 dir=Dt(residual);
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70
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71 [tmp__, pos]=max(abs(dir));
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72 indx(j)=pos;
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73
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74 p(indx)=dir(indx);
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75 Dp=D(p);
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76 pDDp=Dp'*Dp;
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77
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78 if (j==1)
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79 beta=0;
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80 else
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81 beta=-Dp'*residual/pDDp;
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82 end
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83
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84 alfa=residual'*Dp/pDDp;
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85 a=a+alfa*p;
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86 p(indx)=dir(indx)+beta*p(indx);
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87
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88 residual=residual-alfa*Dp;
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89
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90 currResNorm = residual'*residual/n;
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91 if currResNorm<errGoal
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92 fprintf('\nFound exact representation! \n');
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93 break;
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94 end
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95 end;
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96 if (~isempty(indx))
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97 resF(k)=currResNorm;
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98 A(indx,k)=a(indx);
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99 end
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100 end;
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101 return;
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102
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103
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104
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