annotate tests/sl0approx_test.py @ 68:cab8a215f9a1 tip

Minor
author Nic Cleju <nikcleju@gmail.com>
date Tue, 09 Jul 2013 14:50:09 +0300
parents 0d66a0aafb39
children
rev   line source
nikcleju@15 1 # -*- coding: utf-8 -*-
nikcleju@15 2 """
nikcleju@15 3 Created on Sat Nov 05 21:34:49 2011
nikcleju@15 4
nikcleju@15 5 @author: Nic
nikcleju@15 6 """
nikcleju@15 7 import numpy as np
nikcleju@15 8 import numpy.linalg
nikcleju@15 9 import scipy.io
nikcleju@15 10 import unittest
nikcleju@15 11 from pyCSalgos.SL0.SL0_approx import SL0_approx
nikcleju@15 12
nikcleju@15 13 class SL0results(unittest.TestCase):
nikcleju@15 14 def testResults(self):
nikcleju@15 15 mdict = scipy.io.loadmat('SL0approxtestdata.mat')
nikcleju@15 16
nikcleju@15 17 # A = system matrix
nikcleju@15 18 # Y = matrix with measurements (on columns)
nikcleju@15 19 # sigmamin = vector with sigma_min
nikcleju@15 20 for A,Y,eps,sigmamin,Xr in zip(mdict['cellA'].squeeze(),mdict['cellY'].squeeze(),mdict['cellEps'].squeeze(),mdict['sigmamin'].squeeze(),mdict['cellXr'].squeeze()):
nikcleju@15 21 for i in np.arange(Y.shape[1]):
nikcleju@15 22
nikcleju@15 23 # Fix numpy error "LapackError: Parameter a has non-native byte order in lapack_lite.dgesdd"
nikcleju@15 24 A = A.newbyteorder('=')
nikcleju@15 25 Y = Y.newbyteorder('=')
nikcleju@15 26 eps = eps.newbyteorder('=')
nikcleju@15 27 sigmamin = sigmamin.newbyteorder('=')
nikcleju@15 28 Xr = Xr.newbyteorder('=')
nikcleju@15 29
nikcleju@15 30 xr = SL0_approx(A, Y[:,i], eps.squeeze()[i], sigmamin)
nikcleju@15 31
nikcleju@15 32 # check if found solution is the same as the correct cslution
nikcleju@15 33 diff = numpy.linalg.norm(xr - Xr[:,i])
nikcleju@15 34 self.assertTrue(diff < 1e-12)
nikcleju@15 35 # err1 = numpy.linalg.norm(Y[:,i] - np.dot(A,xr))
nikcleju@15 36 # err2 = numpy.linalg.norm(Y[:,i] - np.dot(A,Xr[:,i]))
nikcleju@15 37 # norm1 = numpy.linalg.norm(xr,1)
nikcleju@15 38 # norm2 = numpy.linalg.norm(Xr[:,i],1)
nikcleju@15 39 #
nikcleju@15 40 # # Make a more robust condition:
nikcleju@15 41 # # OK; if solutions are close enough (diff < 1e-6)
nikcleju@15 42 # # or
nikcleju@15 43 # # (
nikcleju@15 44 # # Python solution fulfills the constraint better (or up to 1e-6 worse)
nikcleju@15 45 # # and
nikcleju@15 46 # # Python solution has l1 norm no more than 1e-6 larger as the reference solution
nikcleju@15 47 # # (i.e. either norm1 < norm2 or norm1>norm2 not by more than 1e-6)
nikcleju@15 48 # # )
nikcleju@15 49 # #
nikcleju@15 50 # # ERROR: else
nikcleju@15 51 # differr = err1 - err2 # intentionately no abs(), since err1` < err2 is good
nikcleju@15 52 # diffnorm = norm1 - norm2 # intentionately no abs(), since norm1 < norm2 is good
nikcleju@15 53 # if diff < 1e-6 or (differr < 1e-6 and (diffnorm < 1e-6)):
nikcleju@15 54 # isok = True
nikcleju@15 55 # else:
nikcleju@15 56 # isok = False
nikcleju@15 57 # self.assertTrue(isok)
nikcleju@15 58
nikcleju@15 59 #diff = numpy.linalg.norm(xr - Xr[:,i])
nikcleju@15 60 #if diff > 1e-6:
nikcleju@15 61 # self.assertTrue(diff < 1e-6)
nikcleju@15 62
nikcleju@15 63
nikcleju@15 64 if __name__ == "__main__":
nikcleju@15 65 #import cProfile
nikcleju@15 66 #cProfile.run('unittest.main()', 'profres')
nikcleju@15 67 unittest.main()
nikcleju@15 68 #suite = unittest.TestLoader().loadTestsFromTestCase(CompareResults)
nikcleju@15 69 #unittest.TextTestRunner(verbosity=2).run(suite)