annotate fft/fftw/fftw-3.3.4/rdft/rdft2-inplace-strides.c @ 40:223f770b5341 kissfft-double tip

Try a double-precision kissfft
author Chris Cannam
date Wed, 07 Sep 2016 10:40:32 +0100
parents 26056e866c29
children
rev   line source
Chris@19 1 /*
Chris@19 2 * Copyright (c) 2003, 2007-14 Matteo Frigo
Chris@19 3 * Copyright (c) 2003, 2007-14 Massachusetts Institute of Technology
Chris@19 4 *
Chris@19 5 * This program is free software; you can redistribute it and/or modify
Chris@19 6 * it under the terms of the GNU General Public License as published by
Chris@19 7 * the Free Software Foundation; either version 2 of the License, or
Chris@19 8 * (at your option) any later version.
Chris@19 9 *
Chris@19 10 * This program is distributed in the hope that it will be useful,
Chris@19 11 * but WITHOUT ANY WARRANTY; without even the implied warranty of
Chris@19 12 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
Chris@19 13 * GNU General Public License for more details.
Chris@19 14 *
Chris@19 15 * You should have received a copy of the GNU General Public License
Chris@19 16 * along with this program; if not, write to the Free Software
Chris@19 17 * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
Chris@19 18 *
Chris@19 19 */
Chris@19 20
Chris@19 21
Chris@19 22 #include "rdft.h"
Chris@19 23
Chris@19 24 /* Check if the vecsz/sz strides are consistent with the problem
Chris@19 25 being in-place for vecsz.dim[vdim], or for all dimensions
Chris@19 26 if vdim == RNK_MINFTY. We can't just use tensor_inplace_strides
Chris@19 27 because rdft transforms have the unfortunate property of
Chris@19 28 differing input and output sizes. This routine is not
Chris@19 29 exhaustive; we only return 1 for the most common case. */
Chris@19 30 int X(rdft2_inplace_strides)(const problem_rdft2 *p, int vdim)
Chris@19 31 {
Chris@19 32 INT N, Nc;
Chris@19 33 INT rs, cs;
Chris@19 34 int i;
Chris@19 35
Chris@19 36 for (i = 0; i + 1 < p->sz->rnk; ++i)
Chris@19 37 if (p->sz->dims[i].is != p->sz->dims[i].os)
Chris@19 38 return 0;
Chris@19 39
Chris@19 40 if (!FINITE_RNK(p->vecsz->rnk) || p->vecsz->rnk == 0)
Chris@19 41 return 1;
Chris@19 42 if (!FINITE_RNK(vdim)) { /* check all vector dimensions */
Chris@19 43 for (vdim = 0; vdim < p->vecsz->rnk; ++vdim)
Chris@19 44 if (!X(rdft2_inplace_strides)(p, vdim))
Chris@19 45 return 0;
Chris@19 46 return 1;
Chris@19 47 }
Chris@19 48
Chris@19 49 A(vdim < p->vecsz->rnk);
Chris@19 50 if (p->sz->rnk == 0)
Chris@19 51 return(p->vecsz->dims[vdim].is == p->vecsz->dims[vdim].os);
Chris@19 52
Chris@19 53 N = X(tensor_sz)(p->sz);
Chris@19 54 Nc = (N / p->sz->dims[p->sz->rnk-1].n) *
Chris@19 55 (p->sz->dims[p->sz->rnk-1].n/2 + 1);
Chris@19 56 X(rdft2_strides)(p->kind, p->sz->dims + p->sz->rnk - 1, &rs, &cs);
Chris@19 57
Chris@19 58 /* the factor of 2 comes from the fact that RS is the stride
Chris@19 59 of p->r0 and p->r1, which is twice as large as the strides
Chris@19 60 in the r2r case */
Chris@19 61 return(p->vecsz->dims[vdim].is == p->vecsz->dims[vdim].os
Chris@19 62 && (X(iabs)(2 * p->vecsz->dims[vdim].os)
Chris@19 63 >= X(imax)(2 * Nc * X(iabs)(cs), N * X(iabs)(rs))));
Chris@19 64 }