annotate fft/fftw/fftw-3.3.4/rdft/nop2.c @ 40:223f770b5341 kissfft-double tip

Try a double-precision kissfft
author Chris Cannam
date Wed, 07 Sep 2016 10:40:32 +0100
parents 26056e866c29
children
rev   line source
Chris@19 1 /*
Chris@19 2 * Copyright (c) 2003, 2007-14 Matteo Frigo
Chris@19 3 * Copyright (c) 2003, 2007-14 Massachusetts Institute of Technology
Chris@19 4 *
Chris@19 5 * This program is free software; you can redistribute it and/or modify
Chris@19 6 * it under the terms of the GNU General Public License as published by
Chris@19 7 * the Free Software Foundation; either version 2 of the License, or
Chris@19 8 * (at your option) any later version.
Chris@19 9 *
Chris@19 10 * This program is distributed in the hope that it will be useful,
Chris@19 11 * but WITHOUT ANY WARRANTY; without even the implied warranty of
Chris@19 12 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
Chris@19 13 * GNU General Public License for more details.
Chris@19 14 *
Chris@19 15 * You should have received a copy of the GNU General Public License
Chris@19 16 * along with this program; if not, write to the Free Software
Chris@19 17 * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
Chris@19 18 *
Chris@19 19 */
Chris@19 20
Chris@19 21
Chris@19 22 /* plans for vrank -infty RDFT2s (nothing to do), as well as in-place
Chris@19 23 rank-0 HC2R. Note that in-place rank-0 R2HC is *not* a no-op, because
Chris@19 24 we have to set the imaginary parts of the output to zero. */
Chris@19 25
Chris@19 26 #include "rdft.h"
Chris@19 27
Chris@19 28 static void apply(const plan *ego_, R *r0, R *r1, R *cr, R *ci)
Chris@19 29 {
Chris@19 30 UNUSED(ego_);
Chris@19 31 UNUSED(r0);
Chris@19 32 UNUSED(r1);
Chris@19 33 UNUSED(cr);
Chris@19 34 UNUSED(ci);
Chris@19 35 }
Chris@19 36
Chris@19 37 static int applicable(const solver *ego_, const problem *p_)
Chris@19 38 {
Chris@19 39 const problem_rdft2 *p = (const problem_rdft2 *) p_;
Chris@19 40 UNUSED(ego_);
Chris@19 41
Chris@19 42 return(0
Chris@19 43 /* case 1 : -infty vector rank */
Chris@19 44 || (p->vecsz->rnk == RNK_MINFTY)
Chris@19 45
Chris@19 46 /* case 2 : rank-0 in-place rdft, except that
Chris@19 47 R2HC is not a no-op because it sets the imaginary
Chris@19 48 part to 0 */
Chris@19 49 || (1
Chris@19 50 && p->kind != R2HC
Chris@19 51 && p->sz->rnk == 0
Chris@19 52 && FINITE_RNK(p->vecsz->rnk)
Chris@19 53 && (p->r0 == p->cr)
Chris@19 54 && X(rdft2_inplace_strides)(p, RNK_MINFTY)
Chris@19 55 ));
Chris@19 56 }
Chris@19 57
Chris@19 58 static void print(const plan *ego, printer *p)
Chris@19 59 {
Chris@19 60 UNUSED(ego);
Chris@19 61 p->print(p, "(rdft2-nop)");
Chris@19 62 }
Chris@19 63
Chris@19 64 static plan *mkplan(const solver *ego, const problem *p, planner *plnr)
Chris@19 65 {
Chris@19 66 static const plan_adt padt = {
Chris@19 67 X(rdft2_solve), X(null_awake), print, X(plan_null_destroy)
Chris@19 68 };
Chris@19 69 plan_rdft2 *pln;
Chris@19 70
Chris@19 71 UNUSED(plnr);
Chris@19 72
Chris@19 73 if (!applicable(ego, p))
Chris@19 74 return (plan *) 0;
Chris@19 75 pln = MKPLAN_RDFT2(plan_rdft2, &padt, apply);
Chris@19 76 X(ops_zero)(&pln->super.ops);
Chris@19 77
Chris@19 78 return &(pln->super);
Chris@19 79 }
Chris@19 80
Chris@19 81 static solver *mksolver(void)
Chris@19 82 {
Chris@19 83 static const solver_adt sadt = { PROBLEM_RDFT2, mkplan, 0 };
Chris@19 84 return MKSOLVER(solver, &sadt);
Chris@19 85 }
Chris@19 86
Chris@19 87 void X(rdft2_nop_register)(planner *p)
Chris@19 88 {
Chris@19 89 REGISTER_SOLVER(p, mksolver());
Chris@19 90 }