annotate fft/fftw/fftw-3.3.4/kernel/tile2d.c @ 40:223f770b5341 kissfft-double tip

Try a double-precision kissfft
author Chris Cannam
date Wed, 07 Sep 2016 10:40:32 +0100
parents 26056e866c29
children
rev   line source
Chris@19 1 /*
Chris@19 2 * Copyright (c) 2003, 2007-14 Matteo Frigo
Chris@19 3 * Copyright (c) 2003, 2007-14 Massachusetts Institute of Technology
Chris@19 4 *
Chris@19 5 * This program is free software; you can redistribute it and/or modify
Chris@19 6 * it under the terms of the GNU General Public License as published by
Chris@19 7 * the Free Software Foundation; either version 2 of the License, or
Chris@19 8 * (at your option) any later version.
Chris@19 9 *
Chris@19 10 * This program is distributed in the hope that it will be useful,
Chris@19 11 * but WITHOUT ANY WARRANTY; without even the implied warranty of
Chris@19 12 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
Chris@19 13 * GNU General Public License for more details.
Chris@19 14 *
Chris@19 15 * You should have received a copy of the GNU General Public License
Chris@19 16 * along with this program; if not, write to the Free Software
Chris@19 17 * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
Chris@19 18 *
Chris@19 19 */
Chris@19 20
Chris@19 21 /* out of place 2D copy routines */
Chris@19 22 #include "ifftw.h"
Chris@19 23
Chris@19 24 void X(tile2d)(INT n0l, INT n0u, INT n1l, INT n1u, INT tilesz,
Chris@19 25 void (*f)(INT n0l, INT n0u, INT n1l, INT n1u, void *args),
Chris@19 26 void *args)
Chris@19 27 {
Chris@19 28 INT d0, d1;
Chris@19 29
Chris@19 30 A(tilesz > 0); /* infinite loops otherwise */
Chris@19 31
Chris@19 32 tail:
Chris@19 33 d0 = n0u - n0l;
Chris@19 34 d1 = n1u - n1l;
Chris@19 35
Chris@19 36 if (d0 >= d1 && d0 > tilesz) {
Chris@19 37 INT n0m = (n0u + n0l) / 2;
Chris@19 38 X(tile2d)(n0l, n0m, n1l, n1u, tilesz, f, args);
Chris@19 39 n0l = n0m; goto tail;
Chris@19 40 } else if (/* d1 >= d0 && */ d1 > tilesz) {
Chris@19 41 INT n1m = (n1u + n1l) / 2;
Chris@19 42 X(tile2d)(n0l, n0u, n1l, n1m, tilesz, f, args);
Chris@19 43 n1l = n1m; goto tail;
Chris@19 44 } else {
Chris@19 45 f(n0l, n0u, n1l, n1u, args);
Chris@19 46 }
Chris@19 47 }
Chris@19 48
Chris@19 49 INT X(compute_tilesz)(INT vl, int how_many_tiles_in_cache)
Chris@19 50 {
Chris@19 51 return X(isqrt)(CACHESIZE /
Chris@19 52 (((INT)sizeof(R)) * vl * (INT)how_many_tiles_in_cache));
Chris@19 53 }