comparison toolboxes/FullBNT-1.0.7/bnt/general/mk_named_CPT.m @ 0:e9a9cd732c1e tip

first hg version after svn
author wolffd
date Tue, 10 Feb 2015 15:05:51 +0000
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-1:000000000000 0:e9a9cd732c1e
1 function CPT2 = mk_named_CPT(family_names, names, dag, CPT1)
2 % MK_NAMED_CPT Permute the dimensions of a CPT so they agree with the internal numbering convention
3 % CPT2 = mk_named_CPT(family_names, names, dag, CPT1)
4 %
5 % This is best explained by example.
6 % Consider the following directed acyclic graph
7 %
8 % C
9 % / \
10 % R S
11 % \ /
12 % W
13 %
14 % where all arcs point down.
15 % When we create the CPT for node W, we consider S as its first parent, and R as its
16 % second, and hence write
17 %
18 % S R W
19 % CPT1(1,1,:) = [1.0 0.0];
20 % CPT1(2,1,:) = [0.2 0.8]; % P(W=1 | R=1, S=2) = 0.2
21 % CPT1(1,2,:) = [0.1 0.9];
22 % CPT1(2,2,:) = [0.01 0.99];
23 %
24 % However, when we create the dag using mk_adj_mat, the nodes get topologically sorted,
25 % and by chance, node R preceeds node S in this ordering.
26 % Hence we should have written
27 %
28 % R S W
29 % CPT2(1,1,:) = [1.0 0.0];
30 % CPT2(2,1,:) = [0.1 0.9];
31 % CPT2(1,2,:) = [0.2 0.8]; % P(W=1 | R=1, S=2) = 0.2
32 % CPT2(2,2,:) = [0.01 0.99];
33 %
34 % Since we do not know the order of the nodes in advance, we can write
35 % CPT2 = mk_named_CPT({'S', 'R', 'W'}, names, dag, CPT1)
36 % where 'S', 'R', 'W' are the order of the dimensions we assumed (the child node must be last in this list),
37 % and names{i} is the name of the i'th node.
38
39 n = length(family_names);
40 family_nums = zeros(1,n);
41 for i=1:n
42 family_nums(i) = stringmatch(family_names{i}, names); % was strmatch
43 end
44
45 fam = family(dag, family_nums(end));
46 perm = zeros(1,n);
47 for i=1:n
48 % perm(i) = find(family_nums(i) == fam);
49 perm(i) = find(fam(i) == family_nums);
50 end
51
52 CPT2 = permute(CPT1, perm);